Permutation Rank Calculator – Understanding Lexicographic Order and Unranking
The Permutation Rank Calculator on MyTimeCalculator is a focused tool for working with permutations in lexicographic order. It helps you answer questions such as: “What is the position of this permutation in sorted order?”, “What permutation occupies rank \(r\)?”, “What comes next or just before?” and “How do repeated elements change the counting?”.
Ranking and unranking algorithms are standard in combinatorics, algorithm design, cryptography, coding theory and competitive programming. By turning permutations into integers and back, they provide a bridge between combinatorial structures and numeric indices.
1. Lexicographic Order on Permutations
Lexicographic order on permutations is defined by sorting the underlying elements and then comparing sequences from left to right. Given a list of distinct elements, the first permutation in lexicographic order is the sorted sequence, and the last is the reverse of the sorted sequence. The number of permutations of \(n\) distinct elements is
If a permutation \(\pi\) has rank \(r\) in this order, then exactly \(r\) permutations come before it and \(n! - 1 - r\) permutations come after it. The calculator reports both the 0-based rank (starting at 0) and the 1-based rank (starting at 1), since both conventions are common in textbooks and contest problems.
2. How the Rank of a Permutation Is Computed
For distinct elements, ranking is based on counting how many permutations begin with a prefix that is smaller in lexicographic order. Suppose the sorted elements are
and we want the rank of a permutation \(\pi = (\pi_1,\pi_2,\dots,\pi_n)\). For each position, we:
- Count how many unused elements are smaller than \(\pi_i\).
- Multiply this count by \((n-i)!\), the number of permutations of the remaining positions.
- Add this contribution to the rank and then mark \(\pi_i\) as used.
The total gives the 0-based lexicographic rank. Unranking reverses this logic: it repeatedly divides the rank by descending factorials to pick the appropriate element at each position.
3. Multisets and Repeated Elements
When elements may repeat, the total number of distinct permutations is smaller. If a multiset has \(n\) total elements with type counts \(a_1,a_2,\dots,a_k\) such that \(a_1 + \dots + a_k = n\), the count of distinct permutations is
Ranking under multiset permutations still follows the idea of counting how many permutations start with lexicographically smaller prefixes, but each time we hypothetically place a smaller symbol, the number of completions is computed using the multiset permutation formula with one fewer copy of that symbol.
4. Next and Previous Permutations
The classic algorithm for the next permutation in lexicographic order works in three steps:
- Scan from the right to find the longest non-increasing suffix.
- Swap the pivot element just before the suffix with the smallest element in the suffix that is larger than it.
- Reverse the suffix to get the smallest possible tail.
Applying this procedure repeatedly generates all permutations in lexicographic order. The calculator uses this method to find both the next and previous permutations, and also to move forward by a given number \(k\) steps by combining ranking and unranking.
5. Custom Orderings and Applications
In some settings, elements do not follow the usual numeric or alphabetical order. For example, card suits may be ordered as \(\text{♣}, \text{♦}, \text{♥}, \text{♠}\) or priorities may be given in a custom list. In that case, comparisons between permutations should respect the custom order.
The Permutation Rank Calculator lets you specify a custom order list and then ranks permutations by translating each element into a code based on its position in that list. This is useful in card games, sorting tasks, custom encodings and algorithms that rely on non-standard ordering rules.
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Permutation Rank Calculator FAQs
Frequently Asked Questions
Quick answers to common questions about lexicographic rank, unranking, multisets and next or previous permutations in this calculator.
In 0-based ranking, the first permutation in order has rank 0, the next has rank 1, and so on up to \(n!-1\). In 1-based ranking, the first permutation has rank 1 and the last has rank \(n!\). Many algorithms naturally use 0-based rank, while some textbooks and contest statements prefer 1-based rank. The calculator reports both so you can match the convention in your problem.
The value of \(n!\) grows very quickly. For modest n, the factorial already exceeds billions or trillions, which can still be handled numerically but not listed explicitly. Beyond certain thresholds, floating-point arithmetic can no longer represent all intermediate values reliably. The calculator enforces practical limits to keep results consistent and avoid numerical overflow or underflow in a browser environment.
Yes. The multiset tabs handle repeated elements explicitly. They treat permutations that differ only by swapping identical items as the same arrangement and compute ranks among distinct permutations of the multiset. For purely distinct elements, the dedicated distinct tabs are simpler and slightly faster.
For the standard tabs, elements are treated as strings and sorted using their natural order, which is similar to dictionary order. For example, the order of the symbols might be A < B < C or 1 < 2 < 10 depending on how they are written. If you need a specific ordering that does not match the default, you can use the custom order tab to explicitly define the precedence of each symbol.
Many interview and contest problems involve generating the next permutation, mapping between permutations and ranks, or working with permutations that include repeated elements. This calculator mirrors the underlying ranking and unranking procedures used in code, so you can use it to test examples, verify your implementations and better understand the structure of permutation spaces.